asdcwefew Posted January 20, 2010 Share Posted January 20, 2010 Hi to all,This is all Information I myself have gathered from the MECP Installers Guide book.Alright Here's the Question!I am trying to figure out how much pull on my alternator I am getting from the amp.Here is the formula We use to figure this outI = (Po - n*Po + Po) / VNowI = amperesPo=RMSn=efficiencyV=voltageSo for me its:I = (3000 - .8*3000 + 3000) / 13.8So I do this3000*.8 and i get 24003000-2400=600600+30003600/13.8260.87 This is my amperage draw correct?and if I'm correct for everyone else heres an easier equation for this:I = (2-n)Po/VSo for me this would go1. 2-.8 =1.22. 1.2*3000=36003. 3600/13.8And there we go. 260.87!!!!!Now, We must remember that Most Class D Amplifiers have a 80% Efficiency Rating and Most Class A/B Amplifiers have a 60-70% efficiency Rating! Quote Link to post Share on other sites
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